Updated README.md
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@ -48,12 +48,6 @@ git clone https://github.com/thewhiterabbit/Deploy_Saleor.git
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```
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sudo bash Deploy_Saleor/deploy-saleor.sh
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```
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<li>With sudo, from the home directory, run the deploy-dashboard.sh script.</li>
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```
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sudo bash Deploy_Saleor/deploy-dashboard.sh
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```
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</ol>
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<hr>
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<p>Please <a href="https://github.com/thewhiterabbit/Deploy_Saleor/issues">report any errors as an issue</a> so that they can be addressed.</p>
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45
resources/saleor/wsgi.py
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resources/saleor/wsgi.py
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"""WSGI config for Saleor project.
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This module contains the WSGI application used by Django's development server
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and any production WSGI deployments. It should expose a module-level variable
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named ``application``. Django's ``runserver`` and ``runfcgi`` commands discover
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this application via the ``WSGI_APPLICATION`` setting.
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Usually you will have the standard Django WSGI application here, but it also
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might make sense to replace the whole Django WSGI application with a custom one
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that later delegates to the Django one. For example, you could introduce WSGI
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middleware here, or combine a Django application with an application of another
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framework.
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"""
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import os
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from django.core.wsgi import get_wsgi_application
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from django.utils.functional import SimpleLazyObject
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from saleor.wsgi.health_check import health_check
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def get_allowed_host_lazy():
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from django.conf import settings
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return settings.ALLOWED_HOSTS[0]
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os.environ.setdefault("DJANGO_SETTINGS_MODULE", "saleor.settings")
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application = get_wsgi_application()
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application = health_check(application, "/health/")
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# Warm-up the django application instead of letting it lazy-load
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application(
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{
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"REQUEST_METHOD": "GET",
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"SERVER_NAME": SimpleLazyObject(get_allowed_host_lazy),
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"REMOTE_ADDR": "127.0.0.1",
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"SERVER_PORT": 80,
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"PATH_INFO": "/graphql/",
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"wsgi.input": b"",
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"wsgi.multiprocess": True,
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},
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lambda x, y: None,
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)
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